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$\displaystyle \overline{A}(\phi, p, t) = \Dinv{2\pi}\int_0^{2\pi} A(\lambda, \phi, p, t) \Dd \lambda$

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$\displaystyle A' = A - \overline{A}$

$B$G$"$k(B. $B$3$N$H$-(B $\overline{A'}=0$ , $\partial \overline{A}/\partial\lambda = 0$ $B$H$J$k$3$H$KCm0U(B. (2.1)$B$NBS>uJ?6Q$r9M$($k(B. (2.1)$BCf$N3FNL$rBS>[email protected],$H$:[email protected],$KJ,$1$F=q$/$H(B

$\begin{subequations}\begin{align} \DP{}{t}(\overline{u} + u') & + \frac{\overl... ...theta} + \theta')\notag\\ &= \overline{Q} + Q' \end{align}\end{subequations}$

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$\begin{subequations}\begin{align} \DP{\overline{u}}{t} & + \frac{\overline{u}}... ...rline{\theta}}{p} - \omega'\DP{\theta'}{p} + Q' \end{align}\end{subequations}$

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$\begin{subequations}\begin{align} \DP{\overline{u}}{t}& + \Dinv{a}\overline{v}... ...eta'}{\phi}} - \overline{\omega'\DP{\theta'}{p}} \end{align}\end{subequations}$

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$\displaystyle \Dinv{a\cos\phi}\left[\DP{u'}{\lambda} + \DP{}{\phi}(v'\cos\phi)\right] + \DP{\omega'}{p} = 0$

(2.0.5)

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$\displaystyle \DP{\overline{u}}{t}$	$\displaystyle + \Dinv{a}\overline{v}\DP{\overline{u}}{\phi} + \overline{\omega... ...rline{v} - \frac{\tan\phi}{a}\overline{u}\overline{v} - \overline{X} =\notag$
	$\displaystyle - \Dinv{a\cos\phi}\overline{u'\DP{u'}{\lambda}} - \Dinv{a}\overline{v'\DP{u'}{\phi}} - \overline{\omega'\DP{u'}{p}}\notag$
	$\displaystyle - \Dinv{a\cos\phi}\overline{u'\DP{u'}{\lambda}} - \Dinv{a}\overl... ...}{\phi}} - \overline{u'\DP{\omega'}{p}} + \frac{2\tan\phi}{a}\overline{u'v'}.$

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$\displaystyle - \Dinv{a\cos\phi}\overline{u'\DP{u'}{\lambda}} - \Dinv{a\cos\phi}\overline{u'\DP{u'}{\lambda}}$	$\displaystyle = - \Dinv{a\cos\phi}\overline{\DP{(u')^2}{\lambda}}$
	$\displaystyle = 0,$
$\displaystyle - \Dinv{a}\overline{v'\DP{u'}{\phi}} - \Dinv{a}\overline{u'\DP{v'}{\phi}} + \frac{2\tan\phi}{a}\overline{u'v'}$	$\displaystyle = -\Dinv{a\cos^2\phi}\DP{}{\phi}(\overline{v'u'}\cos^2\phi)$
$\displaystyle - \overline{\omega'\DP{u'}{p}} - \overline{u'\DP{\omega'}{p}}$	$\displaystyle = -\DP{}{p}(\overline{\omega'u'})$

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	$\displaystyle \DP{\overline{u}}{t} + \Dinv{a}\overline{v}\DP{\overline{u}}{\ph... ...ine{v} - \frac{\tan\phi}{a}\overline{u}\overline{v} - \overline{X} = \notag$
	$\displaystyle \hspace{5em} -\Dinv{a\cos^2\phi}\DP{}{\phi}(\overline{v'u'}\cos^2\phi) -\DP{}{p}(\overline{\omega'u'})$

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$\displaystyle \begin{itemize} <tex2html_comment_mark> \item $B1?F0J}Dx<0(B <tex2h... ...'}\cos\phi) - \DP{}{p}(\overline{\omega'\theta'}). \end{align} \end{itemize}$

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